(7x-12)=2(3x+10)

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Solution for (7x-12)=2(3x+10) equation: 



(7x-12)=2(3x+10)

We move all terms to the left:

(7x-12)-(2(3x+10))=0

We get rid of parentheses

7x-(2(3x+10))-12=0



We calculate terms in parentheses: -(2(3x+10)), so:

2(3x+10)

We multiply parentheses

6x+20

Back to the equation:

-(6x+20)



We get rid of parentheses

7x-6x-20-12=0

We add all the numbers together, and all the variables

x-32=0

We move all terms containing x to the left, all other terms to the right

x=32

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