(7x-13)+(x+29)+(3x+5)=180

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Solution for (7x-13)+(x+29)+(3x+5)=180 equation: 



(7x-13)+(x+29)+(3x+5)=180

We move all terms to the left:

(7x-13)+(x+29)+(3x+5)-(180)=0

We get rid of parentheses

7x+x+3x-13+29+5-180=0

We add all the numbers together, and all the variables

11x-159=0

We move all terms containing x to the left, all other terms to the right

11x=159

x=159/11

x=14+5/11

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