(7x-15)+(6x-12)+(75-x)=180

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Solution for (7x-15)+(6x-12)+(75-x)=180 equation: 



(7x-15)+(6x-12)+(75-x)=180

We move all terms to the left:

(7x-15)+(6x-12)+(75-x)-(180)=0

We add all the numbers together, and all the variables

(7x-15)+(6x-12)+(-1x+75)-180=0

We get rid of parentheses

7x+6x-1x-15-12+75-180=0

We add all the numbers together, and all the variables

12x-132=0

We move all terms containing x to the left, all other terms to the right

12x=132

x=132/12

x=11

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