(7x-15)=(x+28)+(4x-3)

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Solution for (7x-15)=(x+28)+(4x-3) equation: 



(7x-15)=(x+28)+(4x-3)

We move all terms to the left:

(7x-15)-((x+28)+(4x-3))=0

We get rid of parentheses

7x-((x+28)+(4x-3))-15=0



We calculate terms in parentheses: -((x+28)+(4x-3)), so:

(x+28)+(4x-3)

We get rid of parentheses

x+4x+28-3

We add all the numbers together, and all the variables

5x+25

Back to the equation:

-(5x+25)



We get rid of parentheses

7x-5x-25-15=0

We add all the numbers together, and all the variables

2x-40=0

We move all terms containing x to the left, all other terms to the right

2x=40

x=40/2

x=20

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