(7x-16)(10x+13)=0

Solution for (7x-16)(10x+13)=0 equation:

(7x-16)(10x+13)=0

We multiply parentheses ..

(+70x^2+91x-160x-208)=0

We get rid of parentheses

70x^2+91x-160x-208=0

We add all the numbers together, and all the variables

70x^2-69x-208=0

a = 70; b = -69; c = -208;
Δ = b2-4ac
Δ = -692-4·70·(-208)
Δ = 63001
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{63001}=251$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-69)-251}{2*70}=\frac{-182}{140}
=-1+3/10
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-69)+251}{2*70}=\frac{320}{140}
=2+2/7
$