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(7x-2)(2x-5)=0
We multiply parentheses ..
(+14x^2-35x-4x+10)=0
We get rid of parentheses
14x^2-35x-4x+10=0
We add all the numbers together, and all the variables
14x^2-39x+10=0
a = 14; b = -39; c = +10;
Δ = b2-4ac
Δ = -392-4·14·10
Δ = 961
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{961}=31$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-39)-31}{2*14}=\frac{8}{28} =2/7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-39)+31}{2*14}=\frac{70}{28} =2+1/2 $
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