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(7x-2)(7x+2)=0
We use the square of the difference formula
49x^2-4=0
a = 49; b = 0; c = -4;
Δ = b2-4ac
Δ = 02-4·49·(-4)
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{784}=28$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-28}{2*49}=\frac{-28}{98} =-2/7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+28}{2*49}=\frac{28}{98} =2/7 $
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