(7x-2)-(-3x+1)=3(1-3x)

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Solution for (7x-2)-(-3x+1)=3(1-3x) equation: 



(7x-2)-(-3x+1)=3(1-3x)

We move all terms to the left:

(7x-2)-(-3x+1)-(3(1-3x))=0

We add all the numbers together, and all the variables

(7x-2)-(-3x+1)-(3(-3x+1))=0

We get rid of parentheses

7x+3x-(3(-3x+1))-2-1=0



We calculate terms in parentheses: -(3(-3x+1)), so:

3(-3x+1)

We multiply parentheses

-9x+3

Back to the equation:

-(-9x+3)



We add all the numbers together, and all the variables

10x-(-9x+3)-3=0

We get rid of parentheses

10x+9x-3-3=0

We add all the numbers together, and all the variables

19x-6=0

We move all terms containing x to the left, all other terms to the right

19x=6

x=6/19

x=6/19

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