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(7x-26)(2x+19)=180
We move all terms to the left:
(7x-26)(2x+19)-(180)=0
We multiply parentheses ..
(+14x^2+133x-52x-494)-180=0
We get rid of parentheses
14x^2+133x-52x-494-180=0
We add all the numbers together, and all the variables
14x^2+81x-674=0
a = 14; b = 81; c = -674;
Δ = b2-4ac
Δ = 812-4·14·(-674)
Δ = 44305
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(81)-\sqrt{44305}}{2*14}=\frac{-81-\sqrt{44305}}{28} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(81)+\sqrt{44305}}{2*14}=\frac{-81+\sqrt{44305}}{28} $
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