(7x-27)=(3x-5)+(x-1)

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Solution for (7x-27)=(3x-5)+(x-1) equation: 



(7x-27)=(3x-5)+(x-1)

We move all terms to the left:

(7x-27)-((3x-5)+(x-1))=0

We get rid of parentheses

7x-((3x-5)+(x-1))-27=0



We calculate terms in parentheses: -((3x-5)+(x-1)), so:

(3x-5)+(x-1)

We get rid of parentheses

3x+x-5-1

We add all the numbers together, and all the variables

4x-6

Back to the equation:

-(4x-6)



We get rid of parentheses

7x-4x+6-27=0

We add all the numbers together, and all the variables

3x-21=0

We move all terms containing x to the left, all other terms to the right

3x=21

x=21/3

x=7

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