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(7x-3)(3x+7)=0
We multiply parentheses ..
(+21x^2+49x-9x-21)=0
We get rid of parentheses
21x^2+49x-9x-21=0
We add all the numbers together, and all the variables
21x^2+40x-21=0
a = 21; b = 40; c = -21;
Δ = b2-4ac
Δ = 402-4·21·(-21)
Δ = 3364
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3364}=58$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(40)-58}{2*21}=\frac{-98}{42} =-2+1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(40)+58}{2*21}=\frac{18}{42} =3/7 $
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