(7x-3)(4x+2)=(2x+6)(14x-1)

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Solution for (7x-3)(4x+2)=(2x+6)(14x-1) equation: 



(7x-3)(4x+2)=(2x+6)(14x-1)

We move all terms to the left:

(7x-3)(4x+2)-((2x+6)(14x-1))=0

We multiply parentheses ..

(+28x^2+14x-12x-6)-((2x+6)(14x-1))=0



We calculate terms in parentheses: -((2x+6)(14x-1)), so:

(2x+6)(14x-1)

We multiply parentheses ..

(+28x^2-2x+84x-6)

We get rid of parentheses

28x^2-2x+84x-6

We add all the numbers together, and all the variables

28x^2+82x-6

Back to the equation:

-(28x^2+82x-6)



We get rid of parentheses

28x^2-28x^2+14x-12x-82x-6+6=0

We add all the numbers together, and all the variables

-80x=0

x=0/-80

x=0

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