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(7x-3)(5x+1)=0
We multiply parentheses ..
(+35x^2+7x-15x-3)=0
We get rid of parentheses
35x^2+7x-15x-3=0
We add all the numbers together, and all the variables
35x^2-8x-3=0
a = 35; b = -8; c = -3;
Δ = b2-4ac
Δ = -82-4·35·(-3)
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{484}=22$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-22}{2*35}=\frac{-14}{70} =-1/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+22}{2*35}=\frac{30}{70} =3/7 $
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