(7x-3)/4x=3/5

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Solution for (7x-3)/4x=3/5 equation:


x in (-oo:+oo)

x*((7*x-3)/4) = 3/5 // - 3/5

x*((7*x-3)/4)-(3/5) = 0

x*((7*x-3)/4)-3/5 = 0

(x*(7*x-3))/4-3/5 = 0

(5*x*(7*x-3))/(4*5)+(-3*4)/(4*5) = 0

5*x*(7*x-3)-3*4 = 0

35*x^2-15*x-12 = 0

35*x^2-15*x-12 = 0

35*x^2-15*x-12 = 0

DELTA = (-15)^2-(-12*4*35)

DELTA = 1905

DELTA > 0

x = (1905^(1/2)+15)/(2*35) or x = (15-1905^(1/2))/(2*35)

x = (1905^(1/2)+15)/70 or x = (15-1905^(1/2))/70

(x-((15-1905^(1/2))/70))*(x-((1905^(1/2)+15)/70)) = 0

((x-((15-1905^(1/2))/70))*(x-((1905^(1/2)+15)/70)))/(4*5) = 0

((x-((15-1905^(1/2))/70))*(x-((1905^(1/2)+15)/70)))/(4*5) = 0 // * 4*5

(x-((15-1905^(1/2))/70))*(x-((1905^(1/2)+15)/70)) = 0

( x-((15-1905^(1/2))/70) )

x-((15-1905^(1/2))/70) = 0 // + (15-1905^(1/2))/70

x = (15-1905^(1/2))/70

( x-((1905^(1/2)+15)/70) )

x-((1905^(1/2)+15)/70) = 0 // + (1905^(1/2)+15)/70

x = (1905^(1/2)+15)/70

x in { (15-1905^(1/2))/70, (1905^(1/2)+15)/70 }

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