(7x-3)2-(2x+4)2=0

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Solution for (7x-3)2-(2x+4)2=0 equation: 



(7x-3)2-(2x+4)2=0

We multiply parentheses

14x-4x-6-8=0

We add all the numbers together, and all the variables

10x-14=0

We move all terms containing x to the left, all other terms to the right

10x=14

x=14/10

x=1+2/5

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