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(7x-32)(6x-18)=180
We move all terms to the left:
(7x-32)(6x-18)-(180)=0
We multiply parentheses ..
(+42x^2-126x-192x+576)-180=0
We get rid of parentheses
42x^2-126x-192x+576-180=0
We add all the numbers together, and all the variables
42x^2-318x+396=0
a = 42; b = -318; c = +396;
Δ = b2-4ac
Δ = -3182-4·42·396
Δ = 34596
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{34596}=186$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-318)-186}{2*42}=\frac{132}{84} =1+4/7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-318)+186}{2*42}=\frac{504}{84} =6 $
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