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(7x-32)=(5x)
We move all terms to the left:
(7x-32)-((5x))=0
determiningTheFunctionDomain (7x-32)-5x=0
We add all the numbers together, and all the variables
-5x+(7x-32)=0
We get rid of parentheses
-5x+7x-32=0
We add all the numbers together, and all the variables
2x-32=0
We move all terms containing x to the left, all other terms to the right
2x=32
x=32/2
x=16
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