(7x-35)/(8x-40)

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Solution for (7x-35)/(8x-40) equation: 


D( x )

8*x-40 = 0

8*x-40 = 0

8*x-40 = 0

8*x-40 = 0 // + 40

8*x = 40 // : 8

x = 40/8

x = 5

x in (-oo:5) U (5:+oo)

(7*x-35)/(8*x-40) = 0

7*x-35 = 0 // + 35

7*x = 35 // : 7

x = 35/7

x = 5

x in { 5} 

x belongs to the empty set

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