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(7x-4)(7x+10)=0
We multiply parentheses ..
(+49x^2+70x-28x-40)=0
We get rid of parentheses
49x^2+70x-28x-40=0
We add all the numbers together, and all the variables
49x^2+42x-40=0
a = 49; b = 42; c = -40;
Δ = b2-4ac
Δ = 422-4·49·(-40)
Δ = 9604
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9604}=98$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(42)-98}{2*49}=\frac{-140}{98} =-1+3/7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(42)+98}{2*49}=\frac{56}{98} =4/7 $
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