(7x-4)+(19)=(10x+3)=52

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Solution for (7x-4)+(19)=(10x+3)=52 equation: 



(7x-4)+(19)=(10x+3)=52

We move all terms to the left:

(7x-4)+(19)-((10x+3))=0

We get rid of parentheses

7x-((10x+3))-4+19=0



We calculate terms in parentheses: -((10x+3)), so:

(10x+3)

We get rid of parentheses

10x+3

Back to the equation:

-(10x+3)



We add all the numbers together, and all the variables

7x-(10x+3)+15=0

We get rid of parentheses

7x-10x-3+15=0

We add all the numbers together, and all the variables

-3x+12=0

We move all terms containing x to the left, all other terms to the right

-3x=-12

x=-12/-3

x=+4

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