(7x-4)+(4x-22)=180

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Solution for (7x-4)+(4x-22)=180 equation: 



(7x-4)+(4x-22)=180

We move all terms to the left:

(7x-4)+(4x-22)-(180)=0

We get rid of parentheses

7x+4x-4-22-180=0

We add all the numbers together, and all the variables

11x-206=0

We move all terms containing x to the left, all other terms to the right

11x=206

x=206/11

x=18+8/11

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