(7x-4)+(5x+2)=38

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Solution for (7x-4)+(5x+2)=38 equation: 



(7x-4)+(5x+2)=38

We move all terms to the left:

(7x-4)+(5x+2)-(38)=0

We get rid of parentheses

7x+5x-4+2-38=0

We add all the numbers together, and all the variables

12x-40=0

We move all terms containing x to the left, all other terms to the right

12x=40

x=40/12

x=3+1/3

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