(7x-4)+3(x-2)=2x+6

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Solution for (7x-4)+3(x-2)=2x+6 equation: 



(7x-4)+3(x-2)=2x+6

We move all terms to the left:

(7x-4)+3(x-2)-(2x+6)=0

We multiply parentheses

(7x-4)+3x-(2x+6)-6=0

We get rid of parentheses

7x+3x-2x-4-6-6=0

We add all the numbers together, and all the variables

8x-16=0

We move all terms containing x to the left, all other terms to the right

8x=16

x=16/8

x=2

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