(7x-4)-(4x-2)=-(x+5)-6x+4

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Solution for (7x-4)-(4x-2)=-(x+5)-6x+4 equation: 



(7x-4)-(4x-2)=-(x+5)-6x+4

We move all terms to the left:

(7x-4)-(4x-2)-(-(x+5)-6x+4)=0

We get rid of parentheses

7x-4x-(-(x+5)-6x+4)-4+2=0



We calculate terms in parentheses: -(-(x+5)-6x+4), so:

-(x+5)-6x+4

We add all the numbers together, and all the variables

-6x-(x+5)+4

We get rid of parentheses

-6x-x-5+4

We add all the numbers together, and all the variables

-7x-1

Back to the equation:

-(-7x-1)



We add all the numbers together, and all the variables

3x-(-7x-1)-2=0

We get rid of parentheses

3x+7x+1-2=0

We add all the numbers together, and all the variables

10x-1=0

We move all terms containing x to the left, all other terms to the right

10x=1

x=1/10

x=1/10

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