(7x-4)=(20-5x)

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Solution for (7x-4)=(20-5x) equation: 



(7x-4)=(20-5x)

We move all terms to the left:

(7x-4)-((20-5x))=0

We add all the numbers together, and all the variables

(7x-4)-((-5x+20))=0

We get rid of parentheses

7x-((-5x+20))-4=0



We calculate terms in parentheses: -((-5x+20)), so:

(-5x+20)

We get rid of parentheses

-5x+20

Back to the equation:

-(-5x+20)



We get rid of parentheses

7x+5x-20-4=0

We add all the numbers together, and all the variables

12x-24=0

We move all terms containing x to the left, all other terms to the right

12x=24

x=24/12

x=2

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