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(7x-5)(4x+7)=136
We move all terms to the left:
(7x-5)(4x+7)-(136)=0
We multiply parentheses ..
(+28x^2+49x-20x-35)-136=0
We get rid of parentheses
28x^2+49x-20x-35-136=0
We add all the numbers together, and all the variables
28x^2+29x-171=0
a = 28; b = 29; c = -171;
Δ = b2-4ac
Δ = 292-4·28·(-171)
Δ = 19993
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(29)-\sqrt{19993}}{2*28}=\frac{-29-\sqrt{19993}}{56} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(29)+\sqrt{19993}}{2*28}=\frac{-29+\sqrt{19993}}{56} $
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