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(7x-5)(5x+3)=0
We multiply parentheses ..
(+35x^2+21x-25x-15)=0
We get rid of parentheses
35x^2+21x-25x-15=0
We add all the numbers together, and all the variables
35x^2-4x-15=0
a = 35; b = -4; c = -15;
Δ = b2-4ac
Δ = -42-4·35·(-15)
Δ = 2116
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2116}=46$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-46}{2*35}=\frac{-42}{70} =-3/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+46}{2*35}=\frac{50}{70} =5/7 $
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