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(7x-5)(8x+2)=0
We multiply parentheses ..
(+56x^2+14x-40x-10)=0
We get rid of parentheses
56x^2+14x-40x-10=0
We add all the numbers together, and all the variables
56x^2-26x-10=0
a = 56; b = -26; c = -10;
Δ = b2-4ac
Δ = -262-4·56·(-10)
Δ = 2916
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2916}=54$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-54}{2*56}=\frac{-28}{112} =-1/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+54}{2*56}=\frac{80}{112} =5/7 $
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