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(7x-5)(9x+6)=0
We multiply parentheses ..
(+63x^2+42x-45x-30)=0
We get rid of parentheses
63x^2+42x-45x-30=0
We add all the numbers together, and all the variables
63x^2-3x-30=0
a = 63; b = -3; c = -30;
Δ = b2-4ac
Δ = -32-4·63·(-30)
Δ = 7569
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{7569}=87$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-87}{2*63}=\frac{-84}{126} =-2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+87}{2*63}=\frac{90}{126} =5/7 $
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