(7x-5)/(2+4x)=8/7

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Solution for (7x-5)/(2+4x)=8/7 equation: 



(7x-5)/(2+4x)=8/7

We move all terms to the left:

(7x-5)/(2+4x)-(8/7)=0



Domain of the equation: (2+4x)!=0

We move all terms containing x to the left, all other terms to the right

4x!=-2

x!=-2/4

x!=-1/2

x∈R



We add all the numbers together, and all the variables

(7x-5)/(4x+2)-(+8/7)=0

We get rid of parentheses

(7x-5)/(4x+2)-8/7=0

We calculate fractions


(49x-35)/(28x+14)+(-32x-16)/(28x+14)=0

We multiply all the terms by the denominator


(49x-35)+(-32x-16)=0

We get rid of parentheses

49x-32x-35-16=0

We add all the numbers together, and all the variables

17x-51=0

We move all terms containing x to the left, all other terms to the right

17x=51

x=51/17

x=3

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