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(7x-5)/(3+x)=2
We move all terms to the left:
(7x-5)/(3+x)-(2)=0
Domain of the equation: (3+x)!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
x!=-3
x∈R
(7x-5)/(x+3)-2=0
We multiply all the terms by the denominator
(7x-5)-2*(x+3)=0
We multiply parentheses
(7x-5)-2x-6=0
We get rid of parentheses
7x-2x-5-6=0
We add all the numbers together, and all the variables
5x-11=0
We move all terms containing x to the left, all other terms to the right
5x=11
x=11/5
x=2+1/5
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