(7x-5)=(2x+8)+(x+19)

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Solution for (7x-5)=(2x+8)+(x+19) equation:



(7x-5)=(2x+8)+(x+19)
We move all terms to the left:
(7x-5)-((2x+8)+(x+19))=0
We get rid of parentheses
7x-((2x+8)+(x+19))-5=0
We calculate terms in parentheses: -((2x+8)+(x+19)), so:
(2x+8)+(x+19)
We get rid of parentheses
2x+x+8+19
We add all the numbers together, and all the variables
3x+27
Back to the equation:
-(3x+27)
We get rid of parentheses
7x-3x-27-5=0
We add all the numbers together, and all the variables
4x-32=0
We move all terms containing x to the left, all other terms to the right
4x=32
x=32/4
x=8

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