(7x-5)=(2x+8)+(x+19)

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Solution for (7x-5)=(2x+8)+(x+19) equation: 



(7x-5)=(2x+8)+(x+19)

We move all terms to the left:

(7x-5)-((2x+8)+(x+19))=0

We get rid of parentheses

7x-((2x+8)+(x+19))-5=0



We calculate terms in parentheses: -((2x+8)+(x+19)), so:

(2x+8)+(x+19)

We get rid of parentheses

2x+x+8+19

We add all the numbers together, and all the variables

3x+27

Back to the equation:

-(3x+27)



We get rid of parentheses

7x-3x-27-5=0

We add all the numbers together, and all the variables

4x-32=0

We move all terms containing x to the left, all other terms to the right

4x=32

x=32/4

x=8

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