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(7x-6)(3x+3)+(3x-1)(2x+3)=0
We multiply parentheses ..
(+21x^2+21x-18x-18)+(3x-1)(2x+3)=0
We get rid of parentheses
21x^2+21x-18x+(3x-1)(2x+3)-18=0
We multiply parentheses ..
21x^2+(+6x^2+9x-2x-3)+21x-18x-18=0
We add all the numbers together, and all the variables
21x^2+(+6x^2+9x-2x-3)+3x-18=0
We get rid of parentheses
21x^2+6x^2+9x-2x+3x-3-18=0
We add all the numbers together, and all the variables
27x^2+10x-21=0
a = 27; b = 10; c = -21;
Δ = b2-4ac
Δ = 102-4·27·(-21)
Δ = 2368
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2368}=\sqrt{64*37}=\sqrt{64}*\sqrt{37}=8\sqrt{37}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-8\sqrt{37}}{2*27}=\frac{-10-8\sqrt{37}}{54} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+8\sqrt{37}}{2*27}=\frac{-10+8\sqrt{37}}{54} $
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