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(7x-6)(4x+4)=0
We multiply parentheses ..
(+28x^2+28x-24x-24)=0
We get rid of parentheses
28x^2+28x-24x-24=0
We add all the numbers together, and all the variables
28x^2+4x-24=0
a = 28; b = 4; c = -24;
Δ = b2-4ac
Δ = 42-4·28·(-24)
Δ = 2704
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2704}=52$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-52}{2*28}=\frac{-56}{56} =-1 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+52}{2*28}=\frac{48}{56} =6/7 $
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