(7x-6)(8x+3)=0

Solution for (7x-6)(8x+3)=0 equation:

(7x-6)(8x+3)=0

We multiply parentheses ..

(+56x^2+21x-48x-18)=0

We get rid of parentheses

56x^2+21x-48x-18=0

We add all the numbers together, and all the variables

56x^2-27x-18=0

a = 56; b = -27; c = -18;
Δ = b2-4ac
Δ = -272-4·56·(-18)
Δ = 4761
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4761}=69$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-27)-69}{2*56}=\frac{-42}{112}
=-3/8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-27)+69}{2*56}=\frac{96}{112}
=6/7
$