(7x-6)+(3x+13)+(2x+19)=180

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Solution for (7x-6)+(3x+13)+(2x+19)=180 equation: 



(7x-6)+(3x+13)+(2x+19)=180

We move all terms to the left:

(7x-6)+(3x+13)+(2x+19)-(180)=0

We get rid of parentheses

7x+3x+2x-6+13+19-180=0

We add all the numbers together, and all the variables

12x-154=0

We move all terms containing x to the left, all other terms to the right

12x=154

x=154/12

x=12+5/6

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