(7x-6)+(3x-5)=(8x+19)

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Solution for (7x-6)+(3x-5)=(8x+19) equation: 



(7x-6)+(3x-5)=(8x+19)

We move all terms to the left:

(7x-6)+(3x-5)-((8x+19))=0

We get rid of parentheses

7x+3x-((8x+19))-6-5=0



We calculate terms in parentheses: -((8x+19)), so:

(8x+19)

We get rid of parentheses

8x+19

Back to the equation:

-(8x+19)



We add all the numbers together, and all the variables

10x-(8x+19)-11=0

We get rid of parentheses

10x-8x-19-11=0

We add all the numbers together, and all the variables

2x-30=0

We move all terms containing x to the left, all other terms to the right

2x=30

x=30/2

x=15

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