(7x-6)/3-(x+2)=4x+2

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Solution for (7x-6)/3-(x+2)=4x+2 equation:



(7x-6)/3-(x+2)=4x+2
We move all terms to the left:
(7x-6)/3-(x+2)-(4x+2)=0
We get rid of parentheses
(7x-6)/3-x-4x-2-2=0
We multiply all the terms by the denominator
(7x-6)-x*3-4x*3-2*3-2*3=0
We add all the numbers together, and all the variables
(7x-6)-x*3-4x*3-12=0
Wy multiply elements
(7x-6)-3x-12x-12=0
We get rid of parentheses
7x-3x-12x-6-12=0
We add all the numbers together, and all the variables
-8x-18=0
We move all terms containing x to the left, all other terms to the right
-8x=18
x=18/-8
x=-2+1/4

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