(7x-6)=(2x+19)+(3x+13)

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Solution for (7x-6)=(2x+19)+(3x+13) equation: 



(7x-6)=(2x+19)+(3x+13)

We move all terms to the left:

(7x-6)-((2x+19)+(3x+13))=0

We get rid of parentheses

7x-((2x+19)+(3x+13))-6=0



We calculate terms in parentheses: -((2x+19)+(3x+13)), so:

(2x+19)+(3x+13)

We get rid of parentheses

2x+3x+19+13

We add all the numbers together, and all the variables

5x+32

Back to the equation:

-(5x+32)



We get rid of parentheses

7x-5x-32-6=0

We add all the numbers together, and all the variables

2x-38=0

We move all terms containing x to the left, all other terms to the right

2x=38

x=38/2

x=19

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