(7x-7)(4x-14)=180

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Solution for (7x-7)(4x-14)=180 equation:



(7x-7)(4x-14)=180
We move all terms to the left:
(7x-7)(4x-14)-(180)=0
We multiply parentheses ..
(+28x^2-98x-28x+98)-180=0
We get rid of parentheses
28x^2-98x-28x+98-180=0
We add all the numbers together, and all the variables
28x^2-126x-82=0
a = 28; b = -126; c = -82;
Δ = b2-4ac
Δ = -1262-4·28·(-82)
Δ = 25060
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{25060}=\sqrt{4*6265}=\sqrt{4}*\sqrt{6265}=2\sqrt{6265}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-126)-2\sqrt{6265}}{2*28}=\frac{126-2\sqrt{6265}}{56} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-126)+2\sqrt{6265}}{2*28}=\frac{126+2\sqrt{6265}}{56} $

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