(7x-8)(-x+2)=0

Solution for (7x-8)(-x+2)=0 equation:

(7x-8)(-x+2)=0

We add all the numbers together, and all the variables

(7x-8)(-1x+2)=0

We multiply parentheses ..

(-7x^2+14x+8x-16)=0

We get rid of parentheses

-7x^2+14x+8x-16=0

We add all the numbers together, and all the variables

-7x^2+22x-16=0

a = -7; b = 22; c = -16;
Δ = b2-4ac
Δ = 222-4·(-7)·(-16)
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(22)-6}{2*-7}=\frac{-28}{-14}
=+2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(22)+6}{2*-7}=\frac{-16}{-14}
=1+1/7
$