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(7x-8)(2x+4)=0
We multiply parentheses ..
(+14x^2+28x-16x-32)=0
We get rid of parentheses
14x^2+28x-16x-32=0
We add all the numbers together, and all the variables
14x^2+12x-32=0
a = 14; b = 12; c = -32;
Δ = b2-4ac
Δ = 122-4·14·(-32)
Δ = 1936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1936}=44$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-44}{2*14}=\frac{-56}{28} =-2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+44}{2*14}=\frac{32}{28} =1+1/7 $
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