(7x-8)(7x+8)=0

Solution for (7x-8)(7x+8)=0 equation:

(7x-8)(7x+8)=0

We use the square of the difference formula

49x^2-64=0

a = 49; b = 0; c = -64;
Δ = b2-4ac
Δ = 02-4·49·(-64)
Δ = 12544
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{12544}=112$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-112}{2*49}=\frac{-112}{98}
=-1+1/7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+112}{2*49}=\frac{112}{98}
=1+1/7
$