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(7x-8)+(5x-4)=(9x+5)
We move all terms to the left:
(7x-8)+(5x-4)-((9x+5))=0
We get rid of parentheses
7x+5x-((9x+5))-8-4=0
We calculate terms in parentheses: -((9x+5)), so:We add all the numbers together, and all the variables
(9x+5)
We get rid of parentheses
9x+5
Back to the equation:
-(9x+5)
12x-(9x+5)-12=0
We get rid of parentheses
12x-9x-5-12=0
We add all the numbers together, and all the variables
3x-17=0
We move all terms containing x to the left, all other terms to the right
3x=17
x=17/3
x=5+2/3
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