(7x-8)=(3x+20)

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Solution for (7x-8)=(3x+20) equation: 



(7x-8)=(3x+20)

We move all terms to the left:

(7x-8)-((3x+20))=0

We get rid of parentheses

7x-((3x+20))-8=0



We calculate terms in parentheses: -((3x+20)), so:

(3x+20)

We get rid of parentheses

3x+20

Back to the equation:

-(3x+20)



We get rid of parentheses

7x-3x-20-8=0

We add all the numbers together, and all the variables

4x-28=0

We move all terms containing x to the left, all other terms to the right

4x=28

x=28/4

x=7

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