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(7x-9)(7x-5)=0
We multiply parentheses ..
(+49x^2-35x-63x+45)=0
We get rid of parentheses
49x^2-35x-63x+45=0
We add all the numbers together, and all the variables
49x^2-98x+45=0
a = 49; b = -98; c = +45;
Δ = b2-4ac
Δ = -982-4·49·45
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{784}=28$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-98)-28}{2*49}=\frac{70}{98} =5/7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-98)+28}{2*49}=\frac{126}{98} =1+2/7 $
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