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(7x-9)+(5x-11)=(9x+1)
We move all terms to the left:
(7x-9)+(5x-11)-((9x+1))=0
We get rid of parentheses
7x+5x-((9x+1))-9-11=0
We calculate terms in parentheses: -((9x+1)), so:We add all the numbers together, and all the variables
(9x+1)
We get rid of parentheses
9x+1
Back to the equation:
-(9x+1)
12x-(9x+1)-20=0
We get rid of parentheses
12x-9x-1-20=0
We add all the numbers together, and all the variables
3x-21=0
We move all terms containing x to the left, all other terms to the right
3x=21
x=21/3
x=7
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