(7x-9)4x=90

Solution for (7x-9)4x=90 equation:

(7x-9)4x=90

We move all terms to the left:

(7x-9)4x-(90)=0

We multiply parentheses

28x^2-36x-90=0

a = 28; b = -36; c = -90;
Δ = b2-4ac
Δ = -362-4·28·(-90)
Δ = 11376
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{11376}=\sqrt{144*79}=\sqrt{144}*\sqrt{79}=12\sqrt{79}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-12\sqrt{79}}{2*28}=\frac{36-12\sqrt{79}}{56}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+12\sqrt{79}}{2*28}=\frac{36+12\sqrt{79}}{56}
$