(7x2-7x+8)=(2x-5)

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Solution for (7x2-7x+8)=(2x-5) equation: 



(7x^2-7x+8)=(2x-5)

We move all terms to the left:

(7x^2-7x+8)-((2x-5))=0

We get rid of parentheses

7x^2-7x-((2x-5))+8=0



We calculate terms in parentheses: -((2x-5)), so:

(2x-5)

We get rid of parentheses

2x-5

Back to the equation:

-(2x-5)



We get rid of parentheses

7x^2-7x-2x+5+8=0

We add all the numbers together, and all the variables

7x^2-9x+13=0

a = 7; b = -9; c = +13;
Δ = b2-4ac
Δ = -92-4·7·13
Δ = -283
Delta is less than zero, so there is no solution for the equation

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