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(7y+16)(3y+22)=0
We multiply parentheses ..
(+21y^2+154y+48y+352)=0
We get rid of parentheses
21y^2+154y+48y+352=0
We add all the numbers together, and all the variables
21y^2+202y+352=0
a = 21; b = 202; c = +352;
Δ = b2-4ac
Δ = 2022-4·21·352
Δ = 11236
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{11236}=106$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(202)-106}{2*21}=\frac{-308}{42} =-7+1/3 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(202)+106}{2*21}=\frac{-96}{42} =-2+2/7 $
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